[tex]\sf p^2 = \dfrac{8 }{3}- 2 = \dfrac{2}{3}[/tex]TRigonometri
Penjelasan dengan langkah-langkah:
jika sin ΞΈ. cos ΞΈ = 0,375 = 3/8 maka
[tex]\sf \dfrac{1}{sin\ \theta} - \dfrac{1}{cos\ \theta} = . . .[/tex]
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[tex]\sf misal \ p = \dfrac{1}{sin\ \theta} - \dfrac{1}{cos\ \theta}[/tex]
[tex]\sf p = \dfrac{cos \ \theta - sin\ \theta}{sin\ \theta. cos\ \theta}[/tex]
[tex]\sf p^2 = \left(\dfrac{cos \ \theta - sin\ \theta}{sin\ \theta. cos\ \theta}\right)^2[/tex]
[tex]\sf p^2 = \dfrac{1 - 2 sin\ \theta. cos \ \theta }{(sin\ \theta. cos\ \theta)^2}[/tex]
[tex]\sf p^2 = \dfrac{1 - 2 (\frac{3}{8})}{(\frac{3}{8})^2}[/tex]
[tex]\sf p^2 = \dfrac{1 - (\frac{6}{8})}{(\frac{9}{64})}\ . . .*)kalikan\ \frac{64}{64}[/tex]
[tex]\sf p^2 = \dfrac{64 - 48}{9} = \dfrac{16}{9}[/tex]
[tex]\sf p = \sqrt {\frac{16}{9}} = \dfrac{4}{3}[/tex]
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